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KimmDara
@KimmDara
August 2022
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Вычислить f ' (0), если f(x) = - (минус перед дробью) (x+1)/(cosx)
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mikael2
Verified answer
Используем (u/v)'=1/v²[u'v-v'u] u=-(x+1) v=cosx
f'=1/cos²x[-1*c0sx+(x+1)(-sinx)]=- (cosx+sinx+xsinx)/cos²x
f'(0)=-1
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Alexandr130398
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Answers & Comments
Verified answer
Используем (u/v)'=1/v²[u'v-v'u] u=-(x+1) v=cosxf'=1/cos²x[-1*c0sx+(x+1)(-sinx)]=- (cosx+sinx+xsinx)/cos²x
f'(0)=-1