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July 2022
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Чему равно tg^2x+1/sinx*1/cosx+ctg^2x,если tgx+ctgx=5
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mostvit
Ответ:
Пошаговое объяснение:
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44559933
Можно подробно расписать последние 3 строчки?
mostvit
Конечно. В третьей строке снизу, не считая ответа, я прибавил и отнял 2sin²xcos²x, чтобы получить квадрат суммы: sin⁴x+2sin²xcos²x+cos⁴x=(sin²x+cos²x)²=1²=1
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Answers & Comments
Ответ:
Пошаговое объяснение: