Ответ:
[tex]\displaystyle 4[/tex]
Объяснение:
[tex]\displaystyley(4y^2+3x^2)=16\ \ \ |\cdot 2\\\\2y(4y^2+3x^2)=32\\\\x(x^2+12y^2)+2y(4y^2+3x^2)=64\\\\x^3 + 6x^2y + 12xy^2 + 8y^3=64\\\\(x+2y)^3=4^3\\\\x+2y=4[/tex]
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Ответ:
[tex]\displaystyle 4[/tex]
Объяснение:
[tex]\displaystyley(4y^2+3x^2)=16\ \ \ |\cdot 2\\\\2y(4y^2+3x^2)=32\\\\x(x^2+12y^2)+2y(4y^2+3x^2)=64\\\\x^3 + 6x^2y + 12xy^2 + 8y^3=64\\\\(x+2y)^3=4^3\\\\x+2y=4[/tex]