Verified answer

[tex]\displaystyle\bf\\\frac{3m}{m^{2} -16m+64} -\frac{5}{m-8} =\frac{3m}{(m-8)^{2} }-\frac{5}{m-8} =\frac{3m-5\cdot(m-8)}{(m-8)^{2} } =\\\\\\=\frac{3m-5m+40}{(m-8)^{2} }=\frac{40-2m}{(m-8)^{2} }[/tex]

Ответ:(2m-40)/(m-8)²

Объяснение:

m²-16m+64=m²-2*m*8+8²=(m-8)²=(m-8)(m-8)

(3m/((m-8)(m-8)))-5/(m-8) общий знаменатель (m-8)(m-8), доп. множитель ко второй дроби (m-8)

(3m-5*(m-8))/(m-8)²=(3m-5m+40)/(m-8)²=(-2m+40)/(m-8)²=(2m-40)/(m-8)²