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НаилХоран
@НаилХоран
June 2022
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дана функция 1)y=2x-1 ; 2)y=x^3+1 . найти y(1) ; y(4); y(n+1); y(n+2)
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Юлечka
1) у(1)=2*1-1=1
у(4)=2*4-1=7
у(n+1)=2(n+1)-1=2n+1
y(n+2)=2(n+2)-1=2n+3
2) y(1)=1^3+1=2
y(4)=4^3+1=65
y(n+1)=(n+1)^3=1=n^3+3n^2+3n+2
y(n+2)=(n+2)^3+1=n^3+6n^2+12n+9
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Answers & Comments
у(4)=2*4-1=7
у(n+1)=2(n+1)-1=2n+1
y(n+2)=2(n+2)-1=2n+3
2) y(1)=1^3+1=2
y(4)=4^3+1=65
y(n+1)=(n+1)^3=1=n^3+3n^2+3n+2
y(n+2)=(n+2)^3+1=n^3+6n^2+12n+9