Дана функция y(x)=-3x^2-4x+5. Найдите y(3-x)
y(3-x)=-3(3-x)^2-4(3-x)+5=-3(9-6x+x^2)-12+4x=-27+18x-3x^2-12+4x=-3x^2+22x-39,
y(3-x)=-3x^2+22x-39.
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y(3-x)=-3(3-x)^2-4(3-x)+5=-3(9-6x+x^2)-12+4x=-27+18x-3x^2-12+4x=-3x^2+22x-39,
y(3-x)=-3x^2+22x-39.