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Acaciadealbat
@Acaciadealbat
July 2022
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Дано:w(C)=10%
w(cl)=89,2%
w(H)=0,8%
M(CxHyClz)=119,5
Найти:CxHyOz=?
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sb222
Нехай СхНуСlz=100г
Тоді m(С)=10г
m(H)=0,8г
m(Cl)=89,2%
x:у;z=(10:12):(0,8:1):(89,2:35)
х:у:z=0,83:0,8:2,5 (:0,8)
x:у:z=1:1:3
отже, формула СНCl₃
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Acaciadealbat
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Answers & Comments
Тоді m(С)=10г
m(H)=0,8г
m(Cl)=89,2%
x:у;z=(10:12):(0,8:1):(89,2:35)
х:у:z=0,83:0,8:2,5 (:0,8)
x:у:z=1:1:3
отже, формула СНCl₃