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Acaciadealbat
@Acaciadealbat
August 2022
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Дано:w(C)=10%
w(cl)=89,2%
w(H)=0,8%
M(CxHyClz)=119,5
Найти:CxHyOz
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kirillkononenko
Пусть у нас есть 100 грамм вещества:n - количество вещества, n=W(x)/M(x)n(C):n(Cl):n(H)=10/12 : 89.2/35.5 : 0.8/1 = 0.8 : 2.51 : 0.8 = ( приблизительно ) 1 :4 : 1CCl3H, CHCl3 - простейшая формула, M(CHCl3)=119.5
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Acaciadealbat
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kirillkononenko
Рад помочь
Alexei78
Дано:w(C)=10%=0.1
w(cl)=89,2%=0.892
w(H)=0,8%=0.008
M(CxHyClz)=119,5
Найти:CxHyClz
CxHyCLz/ 119.5 = 0.1 /12 : 0.08 / 1 : 0.892 / 35.5
CxHyCLz=1 : 1 :3
CHCL3 - трихлорметан
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Acaciadealbat
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Answers & Comments
w(cl)=89,2%=0.892
w(H)=0,8%=0.008
M(CxHyClz)=119,5
Найти:CxHyClz
CxHyCLz/ 119.5 = 0.1 /12 : 0.08 / 1 : 0.892 / 35.5
CxHyCLz=1 : 1 :3
CHCL3 - трихлорметан