Home
О нас
Products
Services
Регистрация
Войти
Поиск
кирилл1346
@кирилл1346
July 2021
1
8
Report
даю 20 баллов помогите с решением написать уравнения
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Удачник66
Verified answer
1) 0,3^x = 0,3
x = 1
2) 0,7^x = (10/7)^3 = (7/10)^(-3)
x = -3
3) 0,4^(4-5x) = (0,4)^(2,5)
4 - 5x = 2,5
5x = 4 - 2,5 = 1,5
x = 0,3
4) (1/6)^(4x-7) = 6^(x-3) = (1/6)^(3-x)
4x - 7 = 3 - x
5x = 10
x = 2
1 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "даю 20 баллов помогите с решением написать уравнения..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1) 0,3^x = 0,3x = 1
2) 0,7^x = (10/7)^3 = (7/10)^(-3)
x = -3
3) 0,4^(4-5x) = (0,4)^(2,5)
4 - 5x = 2,5
5x = 4 - 2,5 = 1,5
x = 0,3
4) (1/6)^(4x-7) = 6^(x-3) = (1/6)^(3-x)
4x - 7 = 3 - x
5x = 10
x = 2