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Кот1818
@Кот1818
July 2022
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Даю 30 баллов! у=е^х Lnx Найти: а) у'''; б) d^2 y
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dakosia99
1) y'=e^x*lnx+(1/x)*e^x;y"=e^x*lnx+(1/x)*e^x+(-1/x^2)*e^x+(1/x)*e^x;y"'=e^x*lnx+(1/x)*e^x+(-1/x^2)*e^x+(1/x)*e^x+(-2/x^3)*e^x+e^x*(-1/x^2)+(-1/x^2)*e^x+e^x*(1/x)=e^x(lnx+(3/x)-(3/x^2)-(2/x^3);2)
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Кот1818
А под б? )))
dakosia99
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