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lolllpop
@lolllpop
May 2021
2
23
Report
ДАЮ МНОГО БАЛЛОВ
РЕШАТЬ ЛЮБОЕ ЗАДАНИЕ,ЛУЧШЕ НЕСКОЛЬКЛ
С ФОТО ЧЕРНОВИКА
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sedinalana
4
a1=12,d=9,8
S5=(2a1+4d)*5/2=(24+4*9,8)*5/2=(12+19,6)*5=31,6*5=158м
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ПрофиЗнания
N4
Арифмитическая прогрессия:
a₁
=12
d=9,8
Sn=2a₁+(n-1)d/2 *n
S₅=2a1+4d/2 * 5 = (a1+2d)*5=5a1+10d=5*12+98=60+98=158
N3
S12 - ?
a2=23
a4=20
a1+d=23
a1+3d=20 Отнимаем
3d-d=20-23
2d=-3
d=-1,5
a1=23-d=23+1,5=24,5
S12=2a1+11d/2 * 12 = (2a1+11d)*6=(49-16,5)*6=32,5*6=195
0 votes
Thanks 0
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Answers & Comments
a1=12,d=9,8
S5=(2a1+4d)*5/2=(24+4*9,8)*5/2=(12+19,6)*5=31,6*5=158м
Арифмитическая прогрессия:
a₁=12
d=9,8
Sn=2a₁+(n-1)d/2 *n
S₅=2a1+4d/2 * 5 = (a1+2d)*5=5a1+10d=5*12+98=60+98=158
N3
S12 - ?
a2=23
a4=20
a1+d=23
a1+3d=20 Отнимаем
3d-d=20-23
2d=-3
d=-1,5
a1=23-d=23+1,5=24,5
S12=2a1+11d/2 * 12 = (2a1+11d)*6=(49-16,5)*6=32,5*6=195