Решение на прикреплённой фотографии
[tex]\displaystyle\bf\\4\sqrt{\frac{15}{8} } =\sqrt{4^{2}\cdot\frac{15}{8} } =\sqrt{16\cdot\frac{15}{8} } =\sqrt{2\cdot 15} =\sqrt{30} \\\\\\\frac{1}{5}\sqrt{750}=\sqrt{\Big(\frac{1}{5} \Big)^{2}\cdot 750 } =\sqrt{\frac{1}{25}\cdot 750 }=\sqrt{30} \\\\\\\sqrt{30}=\sqrt{30} \ \ \ \Rightarrow \ \ \ 4\sqrt{\frac{15}{8} } =\frac{1}{5}\sqrt{750}[/tex]
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Решение на прикреплённой фотографии
[tex]\displaystyle\bf\\4\sqrt{\frac{15}{8} } =\sqrt{4^{2}\cdot\frac{15}{8} } =\sqrt{16\cdot\frac{15}{8} } =\sqrt{2\cdot 15} =\sqrt{30} \\\\\\\frac{1}{5}\sqrt{750}=\sqrt{\Big(\frac{1}{5} \Big)^{2}\cdot 750 } =\sqrt{\frac{1}{25}\cdot 750 }=\sqrt{30} \\\\\\\sqrt{30}=\sqrt{30} \ \ \ \Rightarrow \ \ \ 4\sqrt{\frac{15}{8} } =\frac{1}{5}\sqrt{750}[/tex]