d=2*10^-5 м λ=600*10^-9 м k=?
d*sin φ=k*λ условие максимума
sin φ=1
k=d/λ=2*10^-5/6*10^-7=33
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d=2*10^-5 м λ=600*10^-9 м k=?
d*sin φ=k*λ условие максимума
sin φ=1
k=d/λ=2*10^-5/6*10^-7=33
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