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@УтяМомоТыМойДруг
August 2021
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Докажите неравенство: а) (х + 7)^2 > х(х + 14)
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petux300
(х+7)
²
>х(х+14)
x
²+2x*7+7²>x*x+14x
x²+14x+49>x²+14x
Сокращаем x²,14x
Получаем
49>0
Доказали.
И да,для любого х утверждение будет верным==>>
x∈R
20 votes
Thanks 41
Kixcertborn2
Verified answer
(х+7)²
> х(х+14)
x
²+14x+49 > x²+14x
49>0
36 votes
Thanks 81
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Answers & Comments
x²+2x*7+7²>x*x+14x
x²+14x+49>x²+14x
Сокращаем x²,14x
Получаем
49>0
Доказали.
И да,для любого х утверждение будет верным==>>x∈R
Verified answer
(х+7)² > х(х+14)x²+14x+49 > x²+14x
49>0