Ответ:
Объяснение:
tg195° + ctg195° =(sin195°/cos195°)+cos195°/sin195°=
= (sin²195°+cos²195°)/(sin195°cos195°)=1/(sin195°cos195°)=
=2/(2sin195°cos195°)=2/sin390°=2/sin(360+30°)=2/sin(30°)=2/(1/2)=4
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Ответ:
Объяснение:
tg195° + ctg195° =(sin195°/cos195°)+cos195°/sin195°=
= (sin²195°+cos²195°)/(sin195°cos195°)=1/(sin195°cos195°)=
=2/(2sin195°cos195°)=2/sin390°=2/sin(360+30°)=2/sin(30°)=2/(1/2)=4