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Ответ:

[tex]25 {x}^{3} - 50 {x}^{2} - x + 2 = 0 \\ 25{x}^{2} (x - 2) -(x - 2) = 0 \\ (x - 2)(25 {x}^{2} - 1) = 0 \\ (x - 2)(5x - 1)(5x + 1) = 0 \\ x1 = 2 \\ x2 = \frac{1}{5} \\ x3 = - \frac{1}{5} [/tex]

Відповідь:

Пояснення:

[tex]25x^2(x-2)-(x-2)=0\\(x-2)(25x^2-1)=0\\\left \{ {{x-2=0} \atop {25x^2-1=0}} \right. \\x=2\\x=-\frac{1}{5} \\x=\frac{1}{5}[/tex]