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aravata
@aravata
July 2023
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Під час сріблення вибору за 1 год на катоді виділилося 2 г срібла. Якою приблизно була сила струму в процесі сріблення? ( k=1,12 х10-6 кг/Кл).
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1Manka1
Дано:
t=1год=3600с
m=2г=0,002кг
k=1,12*10-⁶кг/Кл
Знайти:
І-?
m=klt→l=m/(kt)=0,002/1,12*10-⁶*3600)≈0,5А
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Answers & Comments
t=1год=3600с
m=2г=0,002кг
k=1,12*10-⁶кг/Кл
Знайти:
І-?
m=klt→l=m/(kt)=0,002/1,12*10-⁶*3600)≈0,5А