Ответ:
1)
[tex] \frac{27 {a}^{10} {b}^{9} }{36 {a}^{8} {b}^{14} } = \frac{3 {a}^{2} }{4 {b}^{5} } [/tex]
2)
[tex] \frac{ {x}^{2} + 12x + 36 }{36 - {x}^{2} } = \frac{ {(x + 6)}^{2} }{(6 - x)(6 + x)} = \frac{x + 6}{6 - x} [/tex]
3)
[tex] \frac{ {x}^{3} - 125}{2 {x}^{2} - 10x } = \frac{(x - 5)( {x}^{2} + 5x + 25) }{2x(x - 5)} = \frac{ {x}^{2} + 5x + 25 }{2x} [/tex]
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Answers & Comments
Ответ:
1)
[tex] \frac{27 {a}^{10} {b}^{9} }{36 {a}^{8} {b}^{14} } = \frac{3 {a}^{2} }{4 {b}^{5} } [/tex]
2)
[tex] \frac{ {x}^{2} + 12x + 36 }{36 - {x}^{2} } = \frac{ {(x + 6)}^{2} }{(6 - x)(6 + x)} = \frac{x + 6}{6 - x} [/tex]
3)
[tex] \frac{ {x}^{3} - 125}{2 {x}^{2} - 10x } = \frac{(x - 5)( {x}^{2} + 5x + 25) }{2x(x - 5)} = \frac{ {x}^{2} + 5x + 25 }{2x} [/tex]