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vera831
@vera831
June 2022
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если 200 г. воды растворили 100 г. соли, то образованный раствор
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Kohmanenok
1) Находим массу раствора
200+100=300(г)
2) Находим концентрацию раствора
W=m(в-ва)*100%/m(p-pa)
W(соли)=100*100%/300=33,3%
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Answers & Comments
200+100=300(г)
2) Находим концентрацию раствора
W=m(в-ва)*100%/m(p-pa)
W(соли)=100*100%/300=33,3%