если f(x+1)=xf(x)+4 ,то найдите f(2). Created by 2ydgr477. algebra-ru

Ответ:8Объяснение:f(1) = f(0 + 1) = 0·f(0) + 4 = 4f(2) = f(1 + 1) = 1·f(1) + 4 = 4 + 4 = 8

если f(x+1)=xf(x)+4 ,то найдите f(2)...

2ydgr477 @2ydgr477

August 2022 2 8 Report

если f(x+1)=xf(x)+4 ,то найдите f(2)

DNHelper

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Ответ:

Объяснение:

f(1) = f(0 + 1) = 0·f(0) + 4 = 4

f(2) = f(1 + 1) = 1·f(1) + 4 = 4 + 4 = 8

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NNNLLL54

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Ответ:

$f(x+1)=x\cdot f(x)+4\\\\t=x+1\ \ \Rightarrow \ \ x=t-1\ \ ,\ \ f(t)=(t-1)\cdot f(t-1)+4\ \ \Rightarrow \\\\t=2:\ \ f(2)=(2-1)\cdot f(2-1)+4=1\cdot f(1)+4=f(1)+4\\\\t=1:\ \ f(1)=0\cdot f(0)+4=4\\\\f(2)=f(1)+4=4+4=8$

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