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ladafundesh
@ladafundesh
July 2022
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(2/x^2-4+1/2x-x^2) : 1/x^2+4x+4
Решите,плиз.
x^2= х в квадрате
/ = Это знак дроби
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andrianabyblyk
4-8х^2 +х-2х^4/2х^2 * ( х^2+4х+4)
(4-8х^2 +х-2х^4)*(х2+4х+4)/2х^2
4х^2+16х+16-8х^4-32х^3-32х^2+х3+4х^2+4х-2х^6-8х^5-8х^4/2х^2
-24х^2+20х+16-16х^4-31х^3-2х^6-8х^5/2х^2
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ladafundesh
Надо действиями по порядку, сначала в скобках потом за скобками. Так?
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Answers & Comments
(4-8х^2 +х-2х^4)*(х2+4х+4)/2х^2
4х^2+16х+16-8х^4-32х^3-32х^2+х3+4х^2+4х-2х^6-8х^5-8х^4/2х^2
-24х^2+20х+16-16х^4-31х^3-2х^6-8х^5/2х^2