Ответ:
Объяснение:
2x²+5x-7=0
x₁+x₂=-5/2; -7/2 +1=-5/2
x₁x₂=-7/2; -7/2 ·1=-7/2
x₁=-7/2; x₂=1
(2x₁²+3x₁x₂+2x₂²)/(4x₁²x₂+4x₁x₂²)=(2(x₁²+x₂²)+3x₁x₂)/(4x₁x₂(x₁+x₂))=(2((-7/2)²+1²)+3·(-7/2))/(4·(-7/2)·(-5/2))=(49/2 +2/2)/(-7·(-5))=51/2 ·1/35=51/70
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Ответ:
Объяснение:
2x²+5x-7=0
x₁+x₂=-5/2; -7/2 +1=-5/2
x₁x₂=-7/2; -7/2 ·1=-7/2
x₁=-7/2; x₂=1
(2x₁²+3x₁x₂+2x₂²)/(4x₁²x₂+4x₁x₂²)=(2(x₁²+x₂²)+3x₁x₂)/(4x₁x₂(x₁+x₂))=(2((-7/2)²+1²)+3·(-7/2))/(4·(-7/2)·(-5/2))=(49/2 +2/2)/(-7·(-5))=51/2 ·1/35=51/70