Ответ:

[tex]\displaystyle x_1=-\frac{1}{6} \\ \\ x_2=-\frac{1}{3}[/tex]

Объяснение:

[tex]\displaystyle 4(3x+1)^2=6x+2\\\\ 2(3x+1)^2=3x+1\\ \\ 2(9x^2+6x+1)=3x+1\\ \\ 18x^2+12x+2=3x+1\\ \\ 18x+12x+2-3x-1=0\\ \\ 18x^2+6x+3x+1=0\\ \\ 18x^2+9x+1=0\\ \\ D=81-4*18*1=81-72=9\\ \\ x_1 = \frac{-9+3}{36}=\frac{-6}{36}=-\frac{1}{6}\\ \\ x_2=\frac{-9-3}{36}=\frac{-12}{36}=-\frac{1}{3}[/tex]