За законом заломлення
[tex]n_1 \cdot \sin(\theta_1) = n_2 \cdot \sin(\theta_2)[/tex]
[tex]\theta_2 = \arcsin\left(\frac{n_1 \cdot \sin(\theta_1)}{n_2}\right)=\arcsin\left(\dfrac{1\cdot \sin30^\circ}{1.5}\right)=\arcsin \dfrac{1}{3}[/tex]
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За законом заломлення
[tex]n_1 \cdot \sin(\theta_1) = n_2 \cdot \sin(\theta_2)[/tex]
[tex]\theta_2 = \arcsin\left(\frac{n_1 \cdot \sin(\theta_1)}{n_2}\right)=\arcsin\left(\dfrac{1\cdot \sin30^\circ}{1.5}\right)=\arcsin \dfrac{1}{3}[/tex]