Ответ:
F(x)=-x^3+27 [-2;2]
F'(x)=3x^2
3x^2=0
x=0
F(0)=-0^3+27=27
F(-2)=-(-2)^3+27=35
F(2)=-2^3+27=19
F(x)max=35
F(x)min(19)
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Ответ:
F(x)=-x^3+27 [-2;2]
F'(x)=3x^2
3x^2=0
x=0
F(0)=-0^3+27=27
F(-2)=-(-2)^3+27=35
F(2)=-2^3+27=19
F(x)max=35
F(x)min(19)