Решение неравенства log понизу 2 (3х-1)/(х-1) меньше либо равно 2 имеет вид?
(3x-1)/(x-1)<=4
(3x-1)/(x-1)-4<=0
(3x-1-4x+4)/(x-1)<=0
(3-x)/(x-1)<=0
3-x>=0 x<=3
x-1<0 x<1
3-x<=0 x>=3
x-1>0 x>1
(3x-1)/(x-1)>0
3x-1>0 x>1/3
x>1
3x-1<0 x<1/3
ответ
x>=3 U x<1/3
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(3x-1)/(x-1)<=4
(3x-1)/(x-1)-4<=0
(3x-1-4x+4)/(x-1)<=0
(3-x)/(x-1)<=0
3-x>=0 x<=3
x-1<0 x<1
3-x<=0 x>=3
x-1>0 x>1
(3x-1)/(x-1)>0
3x-1>0 x>1/3
x>1
3x-1<0 x<1/3
x-1<0 x<1
ответ
x>=3 U x<1/3