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aksienova81
@aksienova81
July 2022
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найдите координаты точек пересечения графиков функций у=5х и у=6+4/(х-1)
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MizoriesKun
5х=6 + (4/ (х-1))
5х * (х-1) =6* (х-1) +4
5х²-5х =6х-6+4
5х²-11х+2=0
D= 121-40 =81 √D=9
x₁=(11+9)/10=2 y₁=5*2=10
(2; 10)
x₂=(11-9)/10=1/5 у₂=5* 1/5 =1
(1/5 ; 1 )
1 votes
Thanks 3
aksienova81
спасибо большое!!!
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Answers & Comments
5х=6 + (4/ (х-1))
5х * (х-1) =6* (х-1) +4
5х²-5х =6х-6+4
5х²-11х+2=0
D= 121-40 =81 √D=9
x₁=(11+9)/10=2 y₁=5*2=10 (2; 10)
x₂=(11-9)/10=1/5 у₂=5* 1/5 =1 (1/5 ; 1 )