(х-3)^2+(х-4)^2=5Помогите. Created by tima111999. algebra-ru

=========================================Применим формулу квадрата разности:=========================================D = 49 - 4•10 = 9x1 = ( 7 - 3 )/2 = 4/2 = 2x2 = ( 7 + 3 )/2 = 10/2 = 5ОТВЕТ: 2 ; 5

(х-3)^2+(х-4)^2=5Помогите...

tima111999 @tima111999

July 2022 1 6 Report

(х-3)^2+(х-4)^2=5
Помогите

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Mihail001192

Verified answer

=========================================

Применим формулу квадрата разности:

${(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \\ \\$
=========================================

${(x - 3)}^{2} + {(x - 4)}^{2} = 5 \\ {x}^{2} - 6x + 9 + {x}^{2} - 8x + 16 = 5 \\ 2 {x}^{2} - 14x + 20 = 0 \\ {x}^{2} - 7x + 10 = 0 \\$

D = 49 - 4•10 = 9

x1 = ( 7 - 3 )/2 = 4/2 = 2

x2 = ( 7 + 3 )/2 = 10/2 = 5

ОТВЕТ: 2 ; 5

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