Помогите 6 номер срочно. Created by tima111999. algebra-ru

Помогите 6 номер срочно...

MizoriesKun

$a)\; \; 2\sqrt{24}-4\sqrt6+\sqrt{54}=2\sqrt{4\cdot 6}-4\sqrt6+\sqrt{9\cdot 6}=\\\\=4\sqrt{6}-4\sqrt6+3\sqrt6=3\sqrt6\\\\b)\; \; (\sqrt{k}-\sqrt{m})(\sqrt{k}+\sqrt{m})-2k=(\sqrt{k})^2-(\sqrt{m})^2-2k=\\\\=k-m-2k=-k-m=-(k+m)\\\\c)\; \; \sqrt{31-8\sqrt{15}}+\sqrt{15}=\sqrt{15+16-8\sqrt{15}}+\sqrt{15}=\\\\=\sqrt{(4-\sqrt{15})^2}+\sqrt{15}=|4-\sqrt{15}|+\sqrt{15}=4-\sqrt{15}+\sqrt{15}=4$

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NNNLLL54

Verified answer

2√24 -4√6+√54= 2*2√6 - 4√6+3√6= 3√6

(√k- √m)(√k+√m)-2k= √k²- √m² -2k= k-m-2k= -m -k = - (m+k)

√(31 -8√15)+√15 = √(16 -8√15 +15)+√15 =√(√16 -√15)² +√15 =

= √16 -√15 +√15 =√16 =4

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