Найти корни:
1) х(2х+3)(2-х) = 0
2) х + (12/х) = 8
3) 2х³ - 8х = 0
4) (4/х-1) - (4/х+1) = 1
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Найти корни:
1) х(2х+3)(2-х) = 0
2) х + (12/х) = 8
3) 2х³ - 8х = 0
4) (4/х-1) - (4/х+1) = 1
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Answers & Comments
1)x=0 2x+3=0 2-x=0
x=0 x=-3/2 x=2
2)x=2 x=6
3)x(2x²-8)=0
x=0 2x²-8=0
x=0 x²-4=0
x=0 x=2 x=-2