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naanushk
@naanushk
June 2022
1
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Разложите на множители выражение, не группируя члены
[tex] x^{5} + x^{4}y + x^{3}y^{2} + x^{2}y^{3} + xy^{4} + y^{5} = 0[/tex]
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oganezov00
:)
1)ху+хz+6y+6z=xz+6z+xy+6y=z(x+6)+y(x+6)=(x+6)(z+y) ху+хz+6y+6z=x(y+z)+6(y+z)=(y+z)(x+6)
2)4a+4b+bx+ax=4(a+b)+x(a+b)=(a+b)(4+x)
4a+4b+bx+ax=4a+ax+4b+bx=a(4+x)+b(4+x)=(4+x)(a+b)
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Answers & Comments
4a+4b+bx+ax=4a+ax+4b+bx=a(4+x)+b(4+x)=(4+x)(a+b)