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Help help helpи кстати, с Наступающим)...

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$\left \{ {{2x^2+4y^2=24} \atop {4x^2+8y^2=24x}} \right.\; \left \{ {{x^2+2y^2=12} \atop {x^2+2y^2=6x}} \right. \; \left \{ {{x^2+2y^2=12} \atop {6x=12}} \right. \left \{ {{2y^2=12-x^2} \atop {x=2}} \right. \\\\\left \{ {{2y^2=8} \atop {x=2}} \right. \; \left \{ {{y^2=4} \atop {x=2}} \right. \; \left \{ {{y=\pm 2} \atop {x=2}} \right. \; \; \Rightarrow \; \; (-2,2)\; ,\; \; (2,2)$

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Verified answer

2(2х^2+4у^2)=24х

2*24=24х

Х=2

Если х=2, то 4у^2=24-8=16,

У=2 или -2

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