Объяснение:
1) ∣DC→∣ = DC = AB = 6
2) ∣BA→∣ = 6
3) ∣BC→∣ = 8
4) по т.Пифагора
5) ∣OC→∣ = 1/2 (AC→) = (1/2) * 10 =5
6) ∣CO→∣ = ∣OC→∣ =5
7) ∣CA→∣ =10
Ответ:
1) |DC| = |AB| = AB = 6 (ед.)
2) |BA| = AB = 6 (ед.)
3) |BC| = BC = 8 (ед.)
4) по т-ме Пифагора:
AC = √(6² + 8²) = √(36 + 64) = √100 = 10
|OC| = 0,5 * 10 = 5
5) |CO| = |OC| = 5
6) |AC| = AC = 10
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Answers & Comments
Verified answer
Объяснение:
1) ∣DC→∣ = DC = AB = 6
2) ∣BA→∣ = 6
3) ∣BC→∣ = 8
4) по т.Пифагора
5) ∣OC→∣ = 1/2 (AC→) = (1/2) * 10 =5
6) ∣CO→∣ = ∣OC→∣ =5
7) ∣CA→∣ =10
Verified answer
Ответ:
1) |DC| = |AB| = AB = 6 (ед.)
2) |BA| = AB = 6 (ед.)
3) |BC| = BC = 8 (ед.)
4) по т-ме Пифагора:
AC = √(6² + 8²) = √(36 + 64) = √100 = 10
|OC| = 0,5 * 10 = 5
5) |CO| = |OC| = 5
6) |AC| = AC = 10