m≡-3(mod 6); n≡-4(mod 6)⇒3m-4n≡3·(-3)-4·(-4)=-9+16=7≡1(mod 6)
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m≡-3(mod 6); n≡-4(mod 6)⇒3m-4n≡3·(-3)-4·(-4)=-9+16=7≡1(mod 6)
Ответ: 1