Ответ:
#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
double k;
int n;
cin >> k >> n;
for (n; n > 0; n--) cout << k << endl;
}
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Verified answer
Ответ:
#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
double k;
int n;
cin >> k >> n;
for (n; n > 0; n--) cout << k << endl;
}