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denisnishenkov
@denisnishenkov
July 2022
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как решить
2^3-x + 2^1-x >40
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rudlarpar
Надо вынести за скобки 2 в степени 1-х 2^1-x(2^2+1)>40 2^1-x *5>40 2^1-x>8 2^1-x>2^3 1-x>3 -x>2 x<-2
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