Как решить неравенство логарифмическое. Created by PSM. algebra-ru

-2=log(1/7) (1/7)⁻²=log(1/7) 49log(1/7) (4x+1)<log(1/7) 49ОДз:4x+1>0, 4x>-1, x>-(1/4)основание 0<1/7<1, знак неравенства меняем4x+1<49, 4x<48, x<12{x>-1/4x<12ответ: х∈(-1/4; 12)ТатКТатК4x+1>(1/7)^(-!)4x+1>74x>6x>1,5 4x+1>(1/7)^(-2)4x>48 x>12спасибо, написать-то написала, что знак меняем, но (((( . х>-1/4, x>12, => x>12Новые вопросы в АлгебраAB=√(Xb-Xa)2+(Yb-Ya)2 как читается формулаУ шкільній їдальні учнів можна розсадити по чотири за столом. Яку найменшу кількість столівзаймуть учні першого класу, якщо у ньому навчається 25 учн…ів?Пожалуйста помогите!Х + 5/12= 11/12ПлизПожалуйста помогите!Х + 5/12= 11/12Срочно оооопомогите решить пожалуйста, если можно словами тоже чутка объяснить:^)ПОМОГИТЕ ПОЖАЛУЙСТАнужно решить срочноСформулюйте алгоритм розв'язання лінійної нерівності з однією змінноюрозв'яжіть систему рівняньПлиииизззз решите, спасибочки заранее, даю 33 баллаПОМОГИТЕ ПОЖАЛУЙСТА 9 КЛАСССПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Как решить неравенство логарифмическое...

PSM @PSM

July 2022 1 8 Report

Как решить неравенство логарифмическое

Answers & Comments

kirichekov

Verified answer

-2=log(1/7) (1/7)⁻²=log(1/7) 49
log(1/7) (4x+1)<log(1/7) 49
ОДз:4x+1>0, 4x>-1, x>-(1/4)
основание 0<1/7<1, знак неравенства меняем
4x+1<49, 4x<48, x<12
{x>-1/4
x<12
ответ: х∈(-1/4; 12)