sin^2x-cos^2x=0
1-cos2x-1-cos2x=0
cos2x=0
x=p/4+pn/2
sin^2(pi+x) +cos^2(2pi-x) = 0
-sin^2 x+(1-sin^2 x) =0
-sin^2 x +1-sin^2 x =0
-2sin^2 x = -1
2sin^2 x =1
sin^2 x =1/2
sin x = +-sqrt (1/2)
x = arcsin +2Pi*n, n э R
x = - arcsin +2Pi*n, n э R
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Answers & Comments
sin^2x-cos^2x=0
1-cos2x-1-cos2x=0
cos2x=0
x=p/4+pn/2
sin^2(pi+x) +cos^2(2pi-x) = 0
-sin^2 x+(1-sin^2 x) =0
-sin^2 x +1-sin^2 x =0
-2sin^2 x = -1
2sin^2 x =1
sin^2 x =1/2
sin x = +-sqrt (1/2)
x = arcsin +2Pi*n, n э R
x = - arcsin +2Pi*n, n э R