Ответ:

def print_pretty_table(data, cell_sep=' | ', header_separator=True):

   rows = len(data)

   cols = len(data[0])

   col_width = []

   for col in range(cols):

       columns = [data[row][col] for row in range(rows)]

       col_width.append(len(max(columns, key=len)))

   separator = "-+-".join('-' * n for n in col_width)

   for i, row in enumerate(range(rows)):

       if i == 1 and header_separator:

           print(separator)

       result = []

       for col in range(cols):

           item = data[row][col].rjust(col_width[col])

           result.append(item)

       print(cell_sep.join(result))

Добавляем в Customer метод:

   def values(self):

       return self.get_name(), self.get_address(), self.get_telephone(), \

              self.get_email(), self.mailList(),self.get_number()

И итог:

def main():

   customer = Customer('Josh', 'Long st, Dallas TX', '555-987-1549','[email protected]','Y','1153')

   customer1 = Customer('Djon', 'Long st, Dallas TX', '555-987-1549','[email protected]','Y','1153')

   customer2 = Customer('Ser', 'Long st, Dallas TX', '555-987-1549','[email protected]','Y','1153')

   table_data = [

       ['NAME', 'ADDRESS', 'TELEPHONE', 'EMAIL', 'MAIL', 'NUMBER'],

       customer.values(),

       customer1.values(),

       customer2.values(),

   ]

   print_pretty_table(table_data)

Результат:

NAME |            ADDRESS |    TELEPHONE |        EMAIL |                MAIL | NUMBER

-----+--------------------+--------------+--------------+---------------------+-------

Josh | Long st, Dallas TX | 555-987-1549 | [email protected] | On the mailing list |   1153

Djon | Long st, Dallas TX | 555-987-1549 | [email protected] | On the mailing list |   1153

Ser | Long st, Dallas TX | 555-987-1549 | [email protected] | On the

Объяснение: