Ответ:

дано

m(ppa H2SO4) = 98 g

W(H2SO4) = 12.5%

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m(KOH)-?

m(H2SO4) = 98 * 12.5% / 100% = 12.25 g

H2SO4+2KOH-->K2SO4+2H2O

M(H2SO4) = 98g/mol

n(H2SO4) = m/M = 12.25 / 98 = 0.125 mol

n(H2SO4) = 2n(KOH)

n(KOH) = 2*0.125  = 0.25 mol

M(KOH) = 56 /mol

m(KOH) = n*M = 0.25 * 56 = 14 g

ответ 14 г

Объяснение: