December 2021 0 11 Report
Какой объем кислорода и воздуха потратится на сжигание пропана (C3H8) массой 22 г? 1) Дано:
m (C3H8) = 22г

Найти:
V(O2) - ?
V(воздуха) - ?


2. Дано:
m(CH4) = 64г

Найти:
V(O2) - ?
V(воздуха) - ?
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