дано
V(C3H8) = 40 L
------------------------
V(O2)-?
C3H8+5O2-->3CO2+4H2O
V(C3H8) / 1 mol = X(O2) / 5 mol
X (O2) = 40* 5 / 1 = 200 L
ответ 200 л
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дано
V(C3H8) = 40 L
------------------------
V(O2)-?
C3H8+5O2-->3CO2+4H2O
V(C3H8) / 1 mol = X(O2) / 5 mol
X (O2) = 40* 5 / 1 = 200 L
ответ 200 л