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lenakrakatitsa1656
@lenakrakatitsa1656
August 2021
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какой объём CO2 выделится при сгорании 111граммов пропана:?
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ЯковПервый
Дано:
m (C3H8) = 111г
Найти:
V (CO2) - ?
Решение:
C3H8 + 5O2 = 3CO2 + 4H2O
n (C3H8) = m/M = 111 / 44 = 2.5227 моль
n (CO2) = 3n (C3H8) = 3 * 2.5227 = 7.5681 моль
V (CO2) = n * Vm = 7.5681 * 22.4 = 169.52544л
Ответ: V (CO2) = 169.52544л
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Answers & Comments
m (C3H8) = 111г
Найти:
V (CO2) - ?
Решение:
C3H8 + 5O2 = 3CO2 + 4H2O
n (C3H8) = m/M = 111 / 44 = 2.5227 моль
n (CO2) = 3n (C3H8) = 3 * 2.5227 = 7.5681 моль
V (CO2) = n * Vm = 7.5681 * 22.4 = 169.52544л
Ответ: V (CO2) = 169.52544л