Ответ:
∠MNK=180°-∠KMN-∠MKN=180-20-100=60°
∠МNР=180-∠MNK=180-60=120°
∠MPK=(180-∠MNP)/2
∠MPK=(180-120)/2=30°
∠MPK=30°
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Ответ:
∠MNK=180°-∠KMN-∠MKN=180-20-100=60°
∠МNР=180-∠MNK=180-60=120°
∠MPK=(180-∠MNP)/2
∠MPK=(180-120)/2=30°
∠MPK=30°