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VOLKOVA2013
@VOLKOVA2013
July 2022
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Координаты точек А(3;6;2) ,В(-2;0;5),С(4;5;9) наудите угол между векторами АВ и АС…
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армения20171
Cosa=AB•AC/|AB|•|AC|
AB²=5²+6²+3²=25+36+9=70
AC²=(4-3)²+(5-6)²+(9-2)²=1+1+49=51
AB={-2-3;(0-6);5-2}={-5;-6;3}
AC={1;-1;7}
cosa=(-5+6+21)/√70•√51=
22/√(70•51)
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Answers & Comments
AB²=5²+6²+3²=25+36+9=70
AC²=(4-3)²+(5-6)²+(9-2)²=1+1+49=51
AB={-2-3;(0-6);5-2}={-5;-6;3}
AC={1;-1;7}
cosa=(-5+6+21)/√70•√51=
22/√(70•51)