Нехай ∠ACM = ∠MCB = x
Тоді:
∠HCB = ∠MCB - ∠MCH = x - 9°
∠ABC = 2x
ΔCHB: (∠H = 90°)
∠HCB + ∠HBC = 90°
x - 9° + 2x = 90°
3x = 99°
x = 33°
∠ACB = ∠ABC = 2x = 66°
∠CAB = 180° - 2∠ACB = 48°
Відповідь: ∠B = ∠C = 66°, ∠A = 48°
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Нехай ∠ACM = ∠MCB = x
Тоді:
∠HCB = ∠MCB - ∠MCH = x - 9°
∠ABC = 2x
ΔCHB: (∠H = 90°)
∠HCB + ∠HBC = 90°
x - 9° + 2x = 90°
3x = 99°
x = 33°
∠ACB = ∠ABC = 2x = 66°
∠CAB = 180° - 2∠ACB = 48°
Відповідь: ∠B = ∠C = 66°, ∠A = 48°