log 125 по основанию √а = 4, найти log 25 по основанию а.
log(\sqrt{a})125=4
log(a^1/2)5^3=4
6log(a)5=4
log(a)5=4/6=2/3, тогда
log(a)25=2log(a)5=2*2/3=4/3
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log(\sqrt{a})125=4
log(a^1/2)5^3=4
6log(a)5=4
log(a)5=4/6=2/3, тогда
log(a)25=2log(a)5=2*2/3=4/3