log √3_(х-2)*log 5_х=2 log3_(х-2). Created by Liyaa. algebra-ru

log √3_(х-2)*log 5_х=2 log3

DariosI

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$log _{ 3^{1/2} } (x-2)*log _{5}x=2log _{3}(x-2)$
$1/2*log _{ 3} (x-2)*log _{5}x=2log _{3}(x-2)$
$1/2*log _{ 3} (x-2)*log _{5}x-2log _{3}(x-2) =0$
$1/2*log _{ 3} (x-2)*(log _{5}x-4) =0$
$log _{ 3} (x-2)*(log _{5}x-4) =0$
$log _{ 3} (x-2)=0$
х-2=1
х=3
$log _{5}x-4 =0$
$log _{5}x =4$
х=5⁴
х=625

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kirichekov

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Решение во вложении----------------------------

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