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aleshenka99
@aleshenka99
July 2022
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Log0,3 (4x-5) <= log0,3 (5x-8)
решите неравенство
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НатаМалинина
4x-5<=5x-8
-x<= -3
x=>1
ОДЗ:
4x-5>0
5x-6>0
т.е. х>5/4
Ответ:(5/4;+бесконечности)
3 votes
Thanks 4
aleshenka99
Откуда вообще такие цифры?
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Answers & Comments
-x<= -3
x=>1
ОДЗ:
4x-5>0
5x-6>0
т.е. х>5/4
Ответ:(5/4;+бесконечности)