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Marjangul1
@Marjangul1
March 2022
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log2(2x-1)>log2(x-7)
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kirichekov
Verified answer
Log₂(2x-1)>log₂(x-7)
ОДЗ:
=> x>7. x∈(7;∞)
основание логарифма а=2, 2>1. => знак неравенства не меняем.
2x-1>x-7
x>-6.
учитывая ОДЗ, получим:
=> x>7
ответ: x∈(7;∞)
0 votes
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Answers & Comments
Verified answer
Log₂(2x-1)>log₂(x-7)ОДЗ:
=> x>7. x∈(7;∞)
основание логарифма а=2, 2>1. => знак неравенства не меняем.
2x-1>x-7
x>-6.
учитывая ОДЗ, получим:
=> x>7
ответ: x∈(7;∞)